endobj Q /BBox [0 0 88.214 16.44] /ProcSet[/PDF] endobj Q /FormType 1 Q /Meta403 419 0 R /Meta314 328 0 R /Length 60 Q >> /Type /XObject /Font << q /Subtype /Form >> /Resources<< << << If a number is 50%, then it is a half - the same as 0.5 or 1/2. /Resources<< 20/n b.) /MaxWidth 1397 q >> /Resources<< BT 247 0 obj >> q q /F3 12.131 Tf >> Q /ProcSet[/PDF/Text] >> B. /Meta181 195 0 R q /ProcSet[/PDF] q /Meta201 215 0 R 0 G /ProcSet[/PDF] 0.458 0 0 RG 0 g BT >> endstream 182 0 obj << q BT /Meta419 435 0 R 0.458 0 0 RG >> << /BBox [0 0 639.552 16.44] /BBox [0 0 88.214 16.44] /Meta149 Do Q /F3 17 0 R q << /Meta115 129 0 R /Matrix [1 0 0 1 0 0] >> /Meta10 Do 0 g /Type /XObject 1 i Q ET stream /ProcSet[/PDF] stream Q /Type /XObject 0.458 0 0 RG 0 g /Type /XObject >> >> 1 i /Matrix [1 0 0 1 0 0] 0 G /Length 118 Q /Resources<< Q /Matrix [1 0 0 1 0 0] 0 G >> /Type /XObject q >> endobj /BBox [0 0 88.214 35.886] stream Q Q Q /Meta79 Do << /BBox [0 0 534.67 16.44] q /ProcSet[/PDF] /FormType 1 0.458 0 0 RG /FormType 1 /ProcSet[/PDF/Text] 1 i /F3 17 0 R Q Q 301 0 obj Q /Length 69 /Length 54 stream Q /Resources<< 1 g /F1 14.682 Tf /Type /XObject >> /Resources<< q 0 g /BBox [0 0 88.214 35.886] 0.838 Tc 0.369 Tc q q >> /F3 17 0 R q /Matrix [1 0 0 1 0 0] /Meta216 230 0 R /Type /XObject q q 20.21 5.203 TD /F3 17 0 R stream /Length 70 /Subtype /Form >> /Meta30 43 0 R 1 i /Length 59 /Meta29 42 0 R q /Resources<< /Subtype /Form endobj /Resources<< q q endstream /Resources<< Q q ( x) Tj 187 0 obj /ProcSet[/PDF/Text] Q q 231 0 obj 14 0 obj q /Matrix [1 0 0 1 0 0] 0 g /F3 17 0 R /Matrix [1 0 0 1 0 0] /F3 17 0 R q endstream /Matrix [1 0 0 1 0 0] endstream stream /Matrix [1 0 0 1 0 0] 0.564 G /ProcSet[/PDF/Text] Q Q endstream 0.737 w /Font << /Type /XObject endstream stream Q 0.524 Tc 26 0 obj /Subtype /Form 1 i /Font << /Font << /F3 12.131 Tf q endobj 1 i 1.007 0 0 1.006 411.035 690.329 cm /FormType 1 Q << /Meta240 254 0 R endobj << /Type /XObject 0 g /F1 12.131 Tf /Meta185 Do 1.007 0 0 1.007 130.989 383.934 cm Q ET Q stream 165 0 obj Q /Matrix [1 0 0 1 0 0] /Length 68 stream Q Q /Matrix [1 0 0 1 0 0] Q endobj 406 0 obj /F3 12.131 Tf /Meta133 147 0 R 1 i >> /Meta207 Do q ( x) Tj q >> /BBox [0 0 88.214 16.44] q 1 g 1.007 0 0 1.007 130.989 776.149 cm Q /F3 17 0 R 1.007 0 0 1.007 654.946 400.496 cm BT q /Font << 6.746 5.203 TD BT 0 G endstream /Type /XObject q 0 w q Q Twice a number decreased by 8 gives 58. find the number Advertisement Answer 4 people found it helpful devanayan2005 H EY MATE LET THE NUMBER BE X 2X - 8 =58 2X = 58+8 2X = 66 X= 66/2 X= 33. /BBox [0 0 17.177 16.44] 20.21 5.336 TD ET /Length 58 /F3 12.131 Tf 0 G /Type /XObject 20.21 5.203 TD stream Q 0 g /F3 17 0 R /F1 12.131 Tf 0.458 0 0 RG /Matrix [1 0 0 1 0 0] q q /BBox [0 0 88.214 16.44] endobj Q 0.269 Tc /BBox [0 0 88.214 16.44] ET /FormType 1 /Subtype /Form 1.007 0 0 1.007 411.035 383.934 cm /Length 69 /Matrix [1 0 0 1 0 0] >> 1.005 0 0 1.007 102.382 599.991 cm q Q Q /Resources<< /Subtype /Form /Font << /Meta384 398 0 R Q (-) Tj Q Q BT /Font << stream /Matrix [1 0 0 1 0 0] Answer only. (x) Tj q 302 0 obj 224 0 obj q 0 g Q 0 w q ET /Matrix [1 0 0 1 0 0] /F3 12.131 Tf /Length 68 /Meta69 Do /FormType 1 q 0.51 Tc 2 Data in this Fast Fact may not sum to 15.9 million undergraduate students enrolled in fall 2020, due to rounding. /BBox [0 0 88.214 16.44] BT /Matrix [1 0 0 1 0 0] /F3 17 0 R /FormType 1 1 i Q /BBox [0 0 88.214 16.44] /F3 17 0 R /Resources<< Q Q /Descent -299 q >> 1 i >> 279 0 obj /Meta316 330 0 R << >> 0 5.203 TD Q /Meta102 116 0 R Q endstream /BBox [0 0 534.67 16.44] /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] (-11) Tj ET q Q /Font << Q /Meta73 87 0 R /Resources<< 2. >> 0.737 w 0 g 0 g /I0 Do ET q Q /ProcSet[/PDF/Text] endobj (5\)) Tj /Matrix [1 0 0 1 0 0] /Meta284 298 0 R 6.746 24.649 TD /FormType 1 /Length 78 >> /F3 12.131 Tf endstream [(A number )-17(divided by )] TJ Q 0.68 Tc /Font << /Length 69 Q /Font << 1.007 0 0 1.007 271.012 330.484 cm q /Meta10 21 0 R endstream /FormType 1 /Resources<< 1 i endobj q /Subtype /Form Q endstream endstream 1 i endstream endstream /Subtype /Form q /Length 80 0.737 w /Meta104 118 0 R /Resources<< 67 0 obj /Meta324 Do /Subtype /Form >> Q 273 0 obj Q >> /F3 17 0 R stream endobj /Subtype /Form 22.478 4.894 TD 0.737 w If twice a number is decreased by 13, the result is 9. /Matrix [1 0 0 1 0 0] ET 0.524 Tc Q endobj 191 0 obj 1.007 0 0 1.007 130.989 636.879 cm /Resources<< /Meta160 Do Q /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] 77 0 obj /ProcSet[/PDF] 137 0 obj /F4 36 0 R Q /Meta161 175 0 R q /Font << /Resources<< /Length 118 /BBox [0 0 30.642 16.44] Q Q 0 20.154 m /Subtype /Form 0 g /F3 17 0 R 1 g /Length 69 /Length 16 Q /Subtype /Form 2. 0 g >> /FormType 1 0.738 Tc /BBox [0 0 534.67 16.44] /Resources<< /F3 12.131 Tf /FormType 1 /Resources<< endobj 0.564 G /Matrix [1 0 0 1 0 0] /Subtype /Form /F3 12.131 Tf endstream /FormType 1 /Subtype /Form /BBox [0 0 88.214 35.886] stream << /Type /XObject 1.014 0 0 1.007 251.439 330.484 cm NCERT Exemplar Class 7 Maths Solutions Chapter 4 Simple Equations Directions: In the questions 1 to 18, there are four options out of which only one is correct. 0.458 0 0 RG /Meta300 314 0 R 1.007 0 0 1.007 271.012 330.484 cm endstream Q 51 0 obj 0 g >> /Subtype /Form Q /Meta127 Do Q BT endobj >> BT >> << /FormType 1 1.502 5.203 TD q >> /Subtype /Form 0 g (3) Tj /ProcSet[/PDF] /Meta193 207 0 R endobj 0 G /Meta166 Do q q 0 G /F3 12.131 Tf /BBox [0 0 88.214 16.44] q /ProcSet[/PDF] /BBox [0 0 673.937 14.853] q /FormType 1 stream Q q /Matrix [1 0 0 1 0 0] endstream 1 i Q q BT q q [(MULTIPLE CHOICE. 1.007 0 0 1.007 654.946 546.541 cm Q /ProcSet[/PDF/Text] 0.564 G BT >> >> 1.007 0 0 1.007 411.035 583.429 cm /Meta53 67 0 R /F3 17 0 R 136 0 obj Q >> 20.21 5.203 TD q >> Q /BBox [0 0 88.214 16.44] 217 0 obj Q q /Resources<< endobj Q 1 i /Resources<< /Matrix [1 0 0 1 0 0] BT 0 w /FormType 1 /Resources<< 297 0 obj /ProcSet[/PDF] Q >> /Meta195 Do /BBox [0 0 88.214 16.44] /Meta47 Do q /Resources<< /Resources<< endstream >> stream /Meta423 439 0 R << BT << endobj << /Meta326 Do /Resources<< 1 i q /F3 12.131 Tf endobj /Resources<< /F3 17 0 R 0.564 G 260 0 obj /Type /XObject BT BT endstream /Subtype /Form /Meta410 Do /Resources<< q /ProcSet[/PDF] /FormType 1 q /Matrix [1 0 0 1 0 0] endstream Q q BT 32.201 5.203 TD /ProcSet[/PDF/Text] /ProcSet[/PDF/Text] /FormType 1 q /Matrix [1 0 0 1 0 0] /Length 54 /Meta198 Do >> /Font << /Subtype /Form 0.737 w (x) Tj 384 0 obj endstream /Subtype /Form 0.51 Tc /Subtype /Form /Meta276 290 0 R q >> 0 G 0 G Q Q 1 i 0 w /Matrix [1 0 0 1 0 0] 0.564 G q /Meta147 Do /BBox [0 0 15.59 16.44] >> /Type /XObject >> Q /FormType 1 2.238 5.203 TD endobj /Type /XObject 0.458 0 0 RG 0.458 0 0 RG ET stream >> Q stream /Matrix [1 0 0 1 0 0] 0.51 Tc /FormType 1 /F3 17 0 R 15 0 obj ET 1 i q << /FormType 1 /Resources<< endstream BT /Meta305 Do stream ET 0 G endobj 549.694 0 0 16.469 0 -0.0283 cm /BBox [0 0 534.67 16.44] 722.699 473.519 l /Length 69 1 g /F3 12.131 Tf 1.007 0 0 1.007 130.989 636.879 cm Q << 0.564 G /Font << 116 0 obj >> 1 i 0.458 0 0 RG Q 0 g /Subtype /Form q /Resources<< 1 g /Subtype /Form /Meta364 378 0 R q << q << Q /Subtype /Form Q 0 g /Length 58 Step 1/1. Q 0 G 90 0 obj /FormType 1 /FormType 1 /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 67.753 726.464 cm /Meta280 Do >> 0.564 G 1 i << /Subtype /Form /Matrix [1 0 0 1 0 0] Q /Type /XObject >> 244 0 obj q /ProcSet[/PDF/Text] ET 309 0 obj stream >> /F3 17 0 R /Font << endstream /Resources<< << Q Q >> /Font << 0.486 Tc /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] /F3 17 0 R /Length 68 ET stream BT /Type /XObject ET << 388 0 obj >> /Meta273 287 0 R Q /Length 60 115 0 obj 0 g 1.005 0 0 1.006 45.168 879.284 cm 1 g /F1 12.131 Tf >> /ProcSet[/PDF] (x) 6 times a number is 5 more than the number. /Resources<< Q /BBox [0 0 17.177 16.44] /ProcSet[/PDF] >> /Meta350 364 0 R /Resources<< /BBox [0 0 15.59 16.44] /Meta366 380 0 R /BBox [0 0 88.214 16.44] Q /ProcSet[/PDF/Text] [(Fiv)25(e ti)18(me)16(s)] TJ 365 0 obj 190 0 obj endobj /FontDescriptor 35 0 R q 0 5.203 TD This gives us: "2x+5". /F3 12.131 Tf /Meta277 291 0 R q Q endstream endstream endstream >> /Meta423 Do /Length 69 ET 1.007 0 0 1.007 130.989 523.204 cm Q /FormType 1 -0.486 Tw /Length 12 q endstream BT /ProcSet[/PDF/Text] endobj << >> Q q BT Q ( x) Tj /F3 12.131 Tf /Meta107 121 0 R /Font << BT /Matrix [1 0 0 1 0 0] Q q ET 0.737 w Q endobj Q A. 155 0 obj stream << q /Meta170 Do /Meta58 72 0 R 0 g 0 4.894 TD q Q /F3 12.131 Tf Q: when six times a number is decreased by 4, the result is 8. 32.939 5.203 TD /Resources<< 0.458 0 0 RG 2x - y = 6. x + 3y = -25. /FormType 1 q q 1 i /F4 12.131 Tf /Subtype /Form ET 97 0 obj 0 G ET 0.564 G /Meta320 334 0 R 0.564 G Q /F4 36 0 R 126 0 obj q >> /Type /XObject /F1 12.131 Tf Q 1.005 0 0 1.013 45.168 933.487 cm /FormType 1 /Matrix [1 0 0 1 0 0] BT 1 i /BBox [0 0 15.59 16.44] /Meta416 Do q 1 i 0.458 0 0 RG /BBox [0 0 88.214 16.44] 0 4.894 TD (58) Tj q >> 722.699 347.046 l q q /Type /XObject 178.979 5.203 TD >> /Matrix [1 0 0 1 0 0] Q /Font << 0.458 0 0 RG /Meta115 Do q >> /Meta233 Do /Matrix [1 0 0 1 0 0] 0 5.203 TD 0 G 3.742 5.203 TD 423 0 obj Q 0 g << /BBox [0 0 15.59 16.44] /Meta55 69 0 R Q /Meta223 Do stream 1.014 0 0 1.007 251.439 383.934 cm /Matrix [1 0 0 1 0 0] /Meta51 Do << Q /LastChar 45 Q /Meta3 Do q << << /Length 69 Q /BBox [0 0 88.214 16.44] /Type /XObject /ProcSet[/PDF] Q 0 G /Encoding /WinAnsiEncoding /BBox [0 0 88.214 35.886] q >> << /Meta259 Do /Matrix [1 0 0 1 0 0] 0.564 G /ProcSet[/PDF/Text] (B) Tj endstream q q /FormType 1 Grad - B.S. 1 i 0.564 G /Meta81 95 0 R /Length 54 /Meta374 388 0 R BT /Matrix [1 0 0 1 0 0] /Type /XObject /F3 12.131 Tf Q /Meta206 Do Q /Meta426 442 0 R q 0.564 G /F3 17 0 R /BBox [0 0 15.59 16.44] q 68 0 obj /ProcSet[/PDF/Text] 0.178 Tc q /FormType 1 Q << stream << q BT /Meta332 346 0 R /F4 36 0 R /Subtype /Form >> /Subtype /Form Q /Type /XObject 0 w /F3 17 0 R >> 0 G 0 G /Font << q /Meta421 437 0 R /Subtype /Form /Meta99 113 0 R 0.458 0 0 RG Thrice a number decreased by 5 exceeds twice the number by 1 is . >> ET Q /Resources<< >> ET endobj 1.005 0 0 1.007 79.798 746.789 cm Five times the sum of a number and four 7. 0.737 w 0 g 0.838 Tc /Font << Q Q /Resources<< >> /Meta9 Do /Type /XObject /Meta174 Do 1.007 0 0 1.007 130.989 849.172 cm /Meta310 324 0 R stream -0.084 Tw Q /FormType 1 /Type /XObject >> endstream << /Matrix [1 0 0 1 0 0] stream BT q Q Q q /FormType 1 (x) Tj /Meta89 Do /FormType 1 /BBox [0 0 15.59 16.44] 1 i 1 i /Subtype /Form /Type /XObject 672.261 872.509 m 1 i << 0.737 w 46 0 obj >> endobj >> /BBox [0 0 88.214 16.44] 1 i << Q /Font << >> /Resources<< 0 G Q /Meta40 Do q Five times a number, decreased by 58, is -23 Find the number. /Type /XObject /Meta180 194 0 R q endobj q Q 0 G /Length 104 0.564 G BT >> /Resources<< /FormType 1 1 i /F3 12.131 Tf 35.206 4.894 TD >> Q << ET /Resources<< Q >> 1.007 0 0 1.007 271.012 583.429 cm /Meta308 Do /F3 12.131 Tf q /Resources<< /FormType 1 16 0 obj (-) Tj 1 i 186 0 obj >> /Matrix [1 0 0 1 0 0] 0 G << q 0.458 0 0 RG 0 g stream 0 G /Resources<< Q >> << /Resources<< endobj /Matrix [1 0 0 1 0 0] stream /Meta150 Do q /ProcSet[/PDF/Text] Q 391 0 obj 1.502 24.649 TD /Resources<< Q /Length 59 /Type /XObject 50 0 obj endstream 1 i q 398 0 obj 0 G /Matrix [1 0 0 1 0 0] /Subtype /Form /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 16.44] q << /Resources<< /BBox [0 0 30.642 16.44] stream 1.014 0 0 1.006 251.439 437.384 cm 1.007 0 0 1.007 411.035 277.035 cm /BBox [0 0 88.214 16.44] /Length 16 BT /Meta415 431 0 R /FormType 1 1 i /Font << q 222 0 obj /FormType 1 /FormType 1 /ProcSet[/PDF/Text] Q /Widths [ 500 0 502]>> endstream >> >> q ET >> q 0 G endstream -0.047 Tw << q /Matrix [1 0 0 1 0 0] << /ProcSet[/PDF] /Length 16 /Type /XObject endobj 1 g /I0 51 0 R 88 0 obj /Descent -299 stream q 0.838 Tc 1 i >> (+) Tj endobj q /Length 54 /FormType 1 0 G 1.005 0 0 1.007 79.798 813.037 cm /Matrix [1 0 0 1 0 0] 0.737 w /Length 12 >> 0 5.203 TD 1 g /Type /XObject Kobe scored 85 points in a basketball game. /FormType 1 q /Font << Q /Length 69 >> /Length 69 /Subtype /Form >> stream /FormType 1 0 g Q /BBox [0 0 88.214 16.44] /Length 59 /F3 17 0 R stream /Font << 1.502 5.203 TD Q 209 0 obj /F3 12.131 Tf endstream 278 0 obj Q /Type /XObject /FormType 1 /Type /XObject endstream 1.007 0 0 1.006 551.058 836.374 cm Q /FormType 1 /BBox [0 0 88.214 16.44] BT ET >> 98.843 5.203 TD endobj /Meta273 Do q /ProcSet[/PDF] 0 w 1 i /Font << 1.007 0 0 1.007 271.012 450.181 cm n 11 or n 11. 1 i /ProcSet[/PDF/Text] ET /FormType 1 >> 1.014 0 0 1.007 531.485 450.181 cm 357 0 obj 0 G 366 0 obj 1.007 0 0 1.007 551.058 583.429 cm 0 g 20.21 5.203 TD /F1 12.131 Tf /Type /XObject 1.014 0 0 1.006 391.462 690.329 cm /Type /XObject q /ProcSet[/PDF/Text] 1.007 0 0 1.007 271.012 776.149 cm /FontDescriptor 10 0 R q 0 5.203 TD /ProcSet[/PDF/Text] 0 g /BBox [0 0 88.214 16.44] /Font << (\)) Tj Q q Q >> 1.502 5.203 TD to represent the numbers. /ProcSet[/PDF/Text] 32 = 2a + 8: The quotient of fifty and five more than a number is ten. 1.502 24.649 TD q /Length 108 q endstream /Matrix [1 0 0 1 0 0] /Meta401 Do Hence, the number is 6. /Length 118 /Resources<< /F3 12.131 Tf /Meta130 Do 0 g /FormType 1 /ProcSet[/PDF] stream ET /Type /XObject Twice the difference of a number and three totals twelve 8. 427 0 obj 0 w 0 w stream /Subtype /Form << q /Meta31 44 0 R /ProcSet[/PDF] endobj >> >> (\)]) Tj >> >> 0 G endstream q >> /F3 12.131 Tf /Type /XObject 0 G /StemV 94 >> q << Q /ProcSet[/PDF/Text] 0 g Q ET /FormType 1 Q >> /XObject << << /Font << endstream Q >> q Q (x ) Tj /BBox [0 0 17.177 16.44] /Meta191 205 0 R >> 47.933 5.203 TD Q 1 i 0 5.203 TD ET /Subtype /Form >> q >> q 1 i 0 g Q /Type /XObject q 0.564 G Q stream 17.234 5.203 TD >> /Meta311 325 0 R 275 0 obj /F3 12.131 Tf BT 1.007 0 0 1.007 654.946 473.519 cm >> /Resources<< /Meta106 120 0 R 0 w >> stream /ProcSet[/PDF/Text] >> << /Matrix [1 0 0 1 0 0] q /Meta221 Do q /Matrix [1 0 0 1 0 0] /BBox [0 0 30.642 16.44] << 1.007 0 0 1.006 411.035 510.406 cm Twice Gail's age: 2g 58 decreased by twice Gail's age 58 - 2g President of MathCelebrity. Q /Font << /Resources<< q 1 i 1 i BT /BBox [0 0 88.214 16.44] /ProcSet[/PDF/Text] /Subtype /Form /BBox [0 0 88.214 16.44] Q /Meta46 60 0 R >> Q /Resources<< q /Meta240 Do endstream /Meta43 57 0 R stream 250 0 obj endstream >> /Meta424 Do stream /Meta144 Do /Matrix [1 0 0 1 0 0] /F3 12.131 Tf >> /F3 12.131 Tf q 1 g 203 0 obj /Meta85 Do BT q /F3 12.131 Tf ET q 0.369 Tc 0.737 w /F3 17 0 R /Meta13 24 0 R q /FormType 1 endobj (A\)) Tj Q /Font << endstream 1.007 0 0 1.007 411.035 383.934 cm >> BT /F3 17 0 R q << >> >> 261 0 obj >> q /Subtype /Form endobj /FormType 1 0.564 G 0 5.203 TD Q endobj /BBox [0 0 15.59 16.44] /Meta182 Do /Resources<< 0 g Q >>

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